(B) Step $1$: Calculate the initial sum of $100$ items.Sum $= 100 \times 46 = 4600$.Step $2$: Adjust the sum by removing the misread values ($61$ and

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(B) Step $1$: Calculate the initial sum of $100$ items.Sum $= 100 \times 46 = 4600$.Step $2$: Adjust the sum by removing the misread values ($61$ and $34$) and adding the correct values ($16$ and $43$).Corrected Sum $= 4600 - 61 - 34 + 16 + 43 = 4600 - 95 + 59 = 4564$.Step $3$: Since the actual number of items is $90$,divide the corrected sum by $90$.Correct Mean $= \frac{4564}{90} = 50.711... \approx 50.7$.

Competitive Quantitative Aptitude Average Average

Medium

The mean of $100$ items was $46$. Later on,it was discovered that an item $16$ was misread as $61$ and another item $43$ was misread as $34$. It was also found that the number of items was $90$ and not $100$. What is the correct mean?

A
$50$
B
$50.7$
C
$52$
D
$52.7$

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The mean of $100$ items was $46$. Later on,it was discovered that an item $16$ was misread as $61$ and another item $43$ was misread as $34$. It was also found that the number of items was $90$ and not $100$. What is the correct mean?

Similar Questions

The average of marks obtained by $100$ candidates in a certain examination is $30$. If the average marks of passed candidates is $35$ and that of the failed candidates is $10$,what is the number of candidates who passed the examination?

The average age of $36$ students in a group is $14$ years. When the teacher's age is included, the average increases by $1$. What is the teacher's age in years?

The average marks of a group of $20$ students on a test is reduced by $4$ when the topper who scored $90$ marks is replaced by a new student. Find the marks of the new student.

$A$ motorist covered the first $20 \text{ km}$ of his journey in $30 \text{ minutes}$ and the remaining $29 \text{ km}$ in $40 \text{ minutes}$. His average speed in $\text{km/hr}$ is:

With an average speed of $40 \, km/h$,a train reaches its destination on time. If it goes with an average speed of $35 \, km/h$,it reaches late by $15 \, \text{minutes}$. The total journey is (in $km$):

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