A man fires a bullet standing between two cli | vedclass

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(B) Let the distances of the two cliffs from the man be $d_1$ and $d_2$. When the man fires a bullet,the sound travels to the cliff and reflects back

Vedclass · Accepted Answer

$1320$

Vedclass · Answer

(B) Let the distances of the two cliffs from the man be $d_1$ and $d_2$. When the man fires a bullet,the sound travels to the cliff and reflects back to him. The time taken for the first echo is $t_1 = 3 \, s$ and for the second echo is $t_2 = 5 \, s$. The distance traveled by sound for the first echo is $2d_1 = v 	imes t_1$,so $d_1 = \frac{330 	imes 3}{2} = 495 \, m$. The distance traveled by sound for the second echo is $2d_2 = v 	imes t_2$,so $d_2 = \frac{330 	imes 5}{2} = 825 \, m$. The total distance between the two cliffs is $D = d_1 + d_2 = 495 + 825 = 1320 \, m$.

$A$ man fires a bullet standing between two cliffs. The first echo is heard after $3 \, s$ and the second echo is heard after $5 \, s$. If the velocity of sound is $330 \, m/s$,then the distance between the cliffs is .... $m$

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