Two monoatomic ideal gases '1' and '2' of mol | vedclass

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(B) The speed of sound $v$ in an ideal gas is given by the formula $v = \sqrt{\frac{\gamma RT}{M}}$, where $\gamma$ is the adiabatic index, $R$ is the

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$\sqrt{\frac{m_2}{m_1}}$

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(B) The speed of sound $v$ in an ideal gas is given by the formula $v = \sqrt{\frac{\gamma RT}{M}}$, where $\gamma$ is the adiabatic index, $R$ is the universal gas constant, $T$ is the absolute temperature, and $M$ is the molar mass of the gas.For monoatomic gases, the adiabatic index $\gamma$ is the same for both gases, i.e.,$\gamma = 5/3$.Since both gases are kept at the same temperature $T$, the ratio of the speed of sound in gas '$1$' $(v_1)$ to that in gas '$2$' $(v_2)$ is:$\frac{v_1}{v_2} = \frac{\sqrt{\frac{\gamma RT}{m_1}}}{\sqrt{\frac{\gamma RT}{m_2}}}$$\frac{v_1}{v_2} = \sqrt{\frac{m_2}{m_1}}$Thus, the ratio of the speed of sound in gas '$1$' to that in gas '$2$' is $\sqrt{\frac{m_2}{m_1}}$.

Two monoatomic ideal gases '$1$' and '$2$' of molecular masses $m_1$ and $m_2$ respectively are enclosed in separate containers kept at the same temperature. The ratio of the speed of sound in gas '$1$' to that in gas '$2$' is

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