A man goes 10,m towards North,then 20,m towar | vedclass

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Question

(A) The man moves $10\,m$ along the North direction (y-axis) and $20\,m$ along the East direction (x-axis).Let the initial position be the origin $(0,

Vedclass · Accepted Answer

$22.36$

Vedclass · Answer

(A) The man moves $10\,m$ along the North direction (y-axis) and $20\,m$ along the East direction (x-axis).Let the initial position be the origin $(0,0)$.The final position vector is $\vec{r} = 20\hat{i} + 10\hat{j}$.The magnitude of displacement is given by $r = |\vec{r}| = \sqrt{x^2 + y^2}$.$r = \sqrt{20^2 + 10^2} = \sqrt{400 + 100} = \sqrt{500}$.$r = 10\sqrt{5} \approx 10 	imes 2.236 = 22.36\,m$.

$A$ man goes $10\,m$ towards North,then $20\,m$ towards East. The displacement is ........ $m$.

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