(D) When the lift is stationary,the normal force $N$ exerted by the weighing machine is equal to the actual weight $W = mg = 40 \times 10 = 400 \, N$.

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(D) When the lift is stationary,the normal force $N$ exerted by the weighing machine is equal to the actual weight $W = mg = 40 \times 10 = 400 \, N$.When the lift accelerates upwards with an acceleration $a = 2 \, m/s^2$,the apparent weight $W'$ is given by the equation $W' = m(g + a)$.Substituting the values: $W' = 40 \times (10 + 2) = 40 \times 12 = 480 \, N$.Since the weighing machine is calibrated to show weight in $kg$ (where $1 \, kg$ corresponds to $10 \, N$ in this problem),the reading will be $480 / 10 = 48 \, kg$.

Class 11 Physics Newton's Laws of Motion and Friction Apparent weight and Pseudo Force

Medium

$A$ man is standing on a weighing machine placed in a lift. When stationary,his weight is recorded as $40 \, kg$. If the lift is accelerated upwards with an acceleration of $2 \, m/s^2$,then the weight recorded in the machine will be .......... $kg$ $(g = 10 \, m/s^2)$.

A
$32$
B
$40$
C
$42$
D
$48$

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Newton's Laws of Motion and Friction

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Apparent weight and Pseudo Force

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$A$ man is standing on a weighing machine placed in a lift. When stationary,his weight is recorded as $40 \, kg$. If the lift is accelerated upwards with an acceleration of $2 \, m/s^2$,then the weight recorded in the machine will be .......... $kg$ $(g = 10 \, m/s^2)$.

Similar Questions

Two trolleys $A$ and $B$ are moving with accelerations $a$ and $2a$ respectively in the same direction. To an observer in trolley $A$,the magnitude of the pseudo force acting on a block of mass $m$ on trolley $B$ is

An elevator car,whose floor-to-ceiling distance is $2.7 \, m$,starts ascending with a constant acceleration of $1.2 \, m/s^2$. $2 \, s$ after the start,a bolt begins falling from the ceiling of the car. The free-fall time of the bolt is ......... $s$.

$A$ simple pendulum is set up in a trolley which moves to the right with an acceleration $a$ on a horizontal plane. Then the thread of the pendulum in the mean position makes an angle $\theta$ with the vertical.

$A$ body of mass $4 \, kg$ weighs $4.8 \, kg$ when suspended in a moving lift. The acceleration of the lift is

An elevator car whose floor-to-ceiling distance is $2.7\,m$ starts ascending with a constant acceleration of $1.2\,m/s^2$. After $2\,s$ of the start,a bolt falls from the ceiling of the car. The free fall time of the bolt is $(g=9.8\,m/s^2)$.

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