$A$ man measures the period of a simple pendulum inside a stationary lift and finds it to be $T \ s$. If the lift accelerates upwards with an acceleration $g/4$,then the period of the pendulum will be

  • A
    $T$
  • B
    $\frac{T}{4}$
  • C
    $\frac{2T}{\sqrt{5}}$
  • D
    $2T\sqrt{5}$

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