A man sells an article at a loss of 5 %. If h | vedclass

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(C) Let the cost price of the article be $P$.Initial selling price $(S.P._1)$ $= P 	imes (1 - 0.05) = 0.95P$.If the cost price increases by $20 \%$,t

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$500$

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(C) Let the cost price of the article be $P$.Initial selling price $(S.P._1)$ $= P 	imes (1 - 0.05) = 0.95P$.If the cost price increases by $20 \%$,the new cost price $(C.P._2)$ $= P 	imes 1.20 = 1.2P$.The new loss is $40 \%$,so the new selling price $(S.P._2)$ $= 1.2P 	imes (1 - 0.40) = 1.2P 	imes 0.60 = 0.72P$.According to the problem,the difference between the two selling prices is $115$.$S.P._1 - S.P._2 = 115$$0.95P - 0.72P = 115$$0.23P = 115$$P = \frac{115}{0.23} = 500$.Therefore,the cost price of the article is $₹ 500$.

$A$ man sells an article at a loss of $5 \%$. If he had bought it at $20 \%$ more and sold it for $Rs. 115$ less,he would have made a loss of $40 \%$. Find the cost price of the article.

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