A man walks 20,m at an angle 60^{circ} north | vedclass

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(A) The man walks a distance $d = 20\,m$ at an angle $	heta = 60^{\circ}$ north of east.To find the distance travelled towards the east,we calculate

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$10$

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(A) The man walks a distance $d = 20\,m$ at an angle $	heta = 60^{\circ}$ north of east.To find the distance travelled towards the east,we calculate the horizontal component of the displacement vector.The horizontal component is given by $d_x = d \cos(	heta)$.Substituting the given values: $d_x = 20 \cos(60^{\circ})$.Since $\cos(60^{\circ}) = 0.5$,we get $d_x = 20 	imes 0.5 = 10\,m$.Therefore,the man has travelled $10\,m$ towards the east.

$A$ man walks $20\,m$ at an angle $60^{\circ}$ north of east. How far towards the east has he travelled?

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