A mass M hangs on a massless rod of length l | vedclass

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(D) The angular momentum of a particle about a point is given by $\vec{L} = \vec{r} 	imes \vec{p}$.For a mass $M$ moving in a horizontal circle with

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$L_A$ is constant,both in magnitude and direction

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(D) The angular momentum of a particle about a point is given by $\vec{L} = \vec{r} 	imes \vec{p}$.For a mass $M$ moving in a horizontal circle with constant angular velocity $\omega$,the velocity vector $\vec{v}$ is always tangent to the circle.Point $A$ is the center of rotation (or on the axis of rotation). The position vector $\vec{r}_A$ from $A$ to $M$ is in the radial direction,and $\vec{p} = M\vec{v}$ is in the tangential direction. Thus,$\vec{L}_A = \vec{r}_A 	imes M\vec{v}$ is directed along the axis of rotation (positive $z$-direction) and remains constant in both magnitude and direction.Point $B$ is a point on the rod or elsewhere. The position vector $\vec{r}_B$ changes as the mass rotates,and the cross product $\vec{r}_B 	imes M\vec{v}$ will result in a vector that changes direction as the mass moves around the circle.Therefore,$L_A$ is constant in both magnitude and direction.

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