A metal oxide has 40% oxygen by mass. The equ | vedclass

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Question

(A) Let the total mass of the metal oxide be $100 \ g$.Mass of oxygen = $40 \ g$.Mass of metal = $100 - 40 = 60 \ g$.Equivalent weight of oxygen = $\f

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(A) Let the total mass of the metal oxide be $100 \ g$.Mass of oxygen = $40 \ g$.Mass of metal = $100 - 40 = 60 \ g$.Equivalent weight of oxygen = $\frac{16}{2} = 8$.Using the law of equivalence: $\frac{	ext{Mass of metal}}{	ext{Equivalent weight of metal}} = \frac{	ext{Mass of oxygen}}{	ext{Equivalent weight of oxygen}}$.$\frac{60}{E} = \frac{40}{8}$.$E = \frac{60 	imes 8}{40} = \frac{480}{40} = 12$.Therefore,the equivalent weight of the metal is $12$.

$A$ metal oxide has $40\%$ oxygen by mass. The equivalent weight of the metal is:

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