A mixture of 1-chloropropane and 2-chloroprop | vedclass

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(D) Both $1-$chloropropane $(CH_3-CH_2-CH_2-Cl)$ and $2-$chloropropane $(CH_3-CHCl-CH_3)$ undergo dehydrohalogenation (elimination reaction) in the pr

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Propene

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(D) Both $1-$chloropropane $(CH_3-CH_2-CH_2-Cl)$ and $2-$chloropropane $(CH_3-CHCl-CH_3)$ undergo dehydrohalogenation (elimination reaction) in the presence of alcoholic $KOH$ to form propene $(CH_3-CH=CH_2)$.$CH_3-CH_2-CH_2-Cl + KOH (	ext{alc.}) ightarrow CH_3-CH=CH_2 + KCl + H_2O$$CH_3-CHCl-CH_3 + KOH (	ext{alc.}) ightarrow CH_3-CH=CH_2 + KCl + H_2O$Thus,the product obtained in both cases is propene.

$A$ mixture of $1-$chloropropane and $2-$chloropropane when treated with alcoholic $KOH$ gives:

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