Which of the following procedures would be be | vedclass

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(C) The reaction involves the substitution of the benzylic hydrogen with an alkyne group. Step $1$: $NBS$ ($N$-Bromosuccinimide) in $CCl_4$ with heat

Vedclass · Accepted Answer

$i.$ $NBS$ in $CCl_4$ and heat; $ii.$ $CH_3C\equiv C^{(-)}Na^{(+)}$

Vedclass · Answer

(C) The reaction involves the substitution of the benzylic hydrogen with an alkyne group. Step $1$: $NBS$ ($N$-Bromosuccinimide) in $CCl_4$ with heat is a standard reagent for free-radical benzylic bromination of $4$-bromotoluene to form $4$-bromobenzyl bromide. Step $2$: The resulting benzylic bromide is a primary alkyl halide,which undergoes an $S_N2$ reaction with a strong nucleophile like the sodium salt of propyne $(CH_3C\equiv C^{(-)}Na^{(+)})$ to yield the desired product. Thus,option $C$ is the correct procedure.

Which of the following procedures would be best for achieving the following reaction?

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