$A$ monochromatic beam of light is incident at $60^{\circ}$ on one face of an equilateral prism of refractive index $n$ and emerges from the opposite face making an angle $\theta(n)$ with the normal (see the figure). For $n=\sqrt{3}$ the value of $\theta$ is $60^{\circ}$ and $\frac{d \theta}{d n}=m$. The value of $m$ is

$A$ triangular prism of glass is shown in the figure. $A$ ray incident normally to one face is totally reflected,if $\theta = 45^o$. The index of refraction of glass is

$A$ light ray is incident on a prism of angle $A = 60^{\circ}$ and refractive index $\mu = \sqrt{2}$. The angle of incidence at which the emergent ray grazes the surface is given by:

The angle of minimum deviation for a prism is $40^o$ and the angle of the prism is $60^o$. The angle of incidence in this position will be.....$^o$

$A$ light ray is incident on an equilateral prism made of a material with a refractive index of $\sqrt{3}$. Inside the prism,if the light ray moves parallel to the base of the prism,then the angle of incidence of the light ray is: (in $^{\circ}$)

$A$ monochromatic ray of light is incident normally on a thin prism of refracting angle $A$. The ray is deviated through an angle $(1.15)^{\circ}$ in passing through the prism. The ray reflected internally from the second face emerges from the first face making an angle of $(6.3)^{\circ}$ with the incident ray. The refractive index of the prism is