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(D) Let $G$ be the resistance of the galvanometer and $I_g = 10^{-4} \ A$ be the full-scale deflection current.For a voltmeter of range $V = 5 \ V$ wi

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None of these

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(D) Let $G$ be the resistance of the galvanometer and $I_g = 10^{-4} \ A$ be the full-scale deflection current.For a voltmeter of range $V = 5 \ V$ with series resistance $R_s = 2 \ M\Omega = 2 	imes 10^6 \ \Omega$:$V = I_g(R_s + G)$$5 = 10^{-4}(2 	imes 10^6 + G)$$5 	imes 10^4 = 2 	imes 10^6 + G$$G = 50000 - 2000000 = -1950000 \ \Omega$.Since the resistance $G$ cannot be negative,the problem statement contains inconsistent values. However,assuming the intended series resistance was $R_s = 48 \ k\Omega$ (which would yield $G = 2000 \ \Omega$):For an ammeter of range $I = 10 \ mA = 10^{-2} \ A$ with shunt resistance $S$:$S = \frac{I_g G}{I - I_g} = \frac{10^{-4} 	imes 2000}{10^{-2} - 10^{-4}} = \frac{0.2}{0.0099} \approx 20.2 \ \Omega$.Given the provided parameters lead to a physical impossibility,the correct choice is $D$.

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