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(D) The ionization potential is the energy required to remove the most loosely bound electron from an isolated gaseous atom.Ionization potential gener

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$1s^2, 2s^2, 2p^6, 3s^1$

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(D) The ionization potential is the energy required to remove the most loosely bound electron from an isolated gaseous atom.Ionization potential generally decreases down a group as the atomic size increases and the valence electron is further from the nucleus.Among the given options,$1s^1$ is Hydrogen,$1s^2, 2s^2, 2p^6$ is Neon (a noble gas with very high ionization potential),$1s^2, 2s^2, 2p^2$ is Carbon,and $1s^2, 2s^2, 2p^6, 3s^1$ is Sodium.Sodium $(Na)$ is an alkali metal in the third period,and its valence electron is in the $3s$ orbital,which is much further from the nucleus compared to the valence electrons of the other elements listed.Therefore,the configuration $1s^2, 2s^2, 2p^6, 3s^1$ corresponds to the lowest ionization potential.

$A$ neutral atom will have the lowest ionization potential when its electronic configuration is

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