A number, when divided successively by 4, 5 a | vedclass

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Question

(C) Observe the difference between the divisor and the remainder in each case:
$4 - 2 = 2$  
$5 - 3 = 2$  
$6 - 4 = 2$
Since the differe

Vedclass · Accepted Answer

$58$

Vedclass · Answer

(C) Observe the difference between the divisor and the remainder in each case:
$4 - 2 = 2$  
$5 - 3 = 2$  
$6 - 4 = 2$
Since the difference is constant $(2)$, the required number is of the form
$	ext{LCM of } 4, 5, 6 - 2$.
First, find the LCM of $4, 5$ and $6$:
$4 = 2^2$  
$5 = 5^1$  
$6 = 2 	imes 3$
$	ext{LCM} = 2^2 	imes 3 	imes 5 = 4 	imes 3 	imes 5 = 60$
Therefore, the least such number is:
$60 - 2 = 58$

$A$ number, when divided successively by $4, 5$ and $6$, leaves remainders $2, 3$ and $4$ respectively. The least such number is

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