A pan balance has a container of water with a | vedclass

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(B) When the brass weight is lowered into the water,it displaces a volume of water equal to its submerged volume. This displaced water flows out throu

Vedclass · Accepted Answer

Water overflows and the left side of the balance tips down.

Vedclass · Answer

(B) When the brass weight is lowered into the water,it displaces a volume of water equal to its submerged volume. This displaced water flows out through the overflow spout into the container on the left-hand pan.According to Archimedes' principle,the brass weight experiences an upward buoyant force equal to the weight of the displaced water. By Newton's third law,the brass weight exerts an equal and opposite downward force on the water,which is transmitted to the right-hand pan.Since the weight of the water displaced is added to the left-hand pan,the total weight on the left side increases. The right-hand pan experiences an additional downward force equal to the buoyant force,but since the water level remains constant at the spout,the total weight on the right side remains unchanged (the weight of the brass object is supported by the string,not the pan). Therefore,the left side of the balance tips down.

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