A parallel combination of two resistors,of 1 | vedclass

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Question

(A) First,calculate the equivalent resistance of the two $1 \,\Omega$ resistors connected in parallel:$R_p = \frac{1 	imes 1}{1 + 1} = 0.5 \,\Omega$.

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(A) First,calculate the equivalent resistance of the two $1 \,\Omega$ resistors connected in parallel:$R_p = \frac{1 	imes 1}{1 + 1} = 0.5 \,\Omega$.Next,calculate the total resistance of the circuit by adding the series resistor:$R_{total} = R_p + 1.5 \,\Omega = 0.5 \,\Omega + 1.5 \,\Omega = 2.0 \,\Omega$.Finally,use Ohm's law to find the current $I$ flowing in the circuit:$I = \frac{V}{R_{total}} = \frac{10 \,V}{2.0 \,\Omega} = 5 \,A$.

$A$ parallel combination of two resistors,of $1 \,\Omega$ each,is connected in series with a $1.5 \,\Omega$ resistor. The total combination is connected across a $10 \,V$ battery. The current flowing in the circuit is .............. $A$

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