The equivalent resistance between the points | vedclass

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(C) The circuit is a Wheatstone bridge-like structure. Due to symmetry,the potential at the center point is the same as the potential at the midpoint

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(C) The circuit is a Wheatstone bridge-like structure. Due to symmetry,the potential at the center point is the same as the potential at the midpoint of the diagonals. However,a simpler way to solve this is by using the symmetry of the circuit.Let the points be $A, B, C, D$. The resistance between $A$ and $B$ is to be found.By symmetry,the circuit can be simplified. The resistors connected to the center point can be treated as parallel branches.Alternatively,using the symmetry of the circuit,the equivalent resistance $R_{eq}$ between $A$ and $B$ is given by the parallel combination of the paths.For this specific symmetric circuit with all resistors equal to $R = 15 \Omega$,the equivalent resistance between any two adjacent corners is $R_{eq} = \frac{2}{3}R$.$R_{eq} = \frac{2}{3} 	imes 15 \Omega = 10 \Omega$.

The equivalent resistance between the points $A$ and $B$ will be (each resistance is $15 \Omega$): (in $\Omega$)

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