A parallel plate air capacitor has capacity C | vedclass

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(C) The force of attraction $F$ between the plates of a parallel plate capacitor is given by the formula:$F = \frac{Q^2}{2 \varepsilon_0 A}$where $Q$

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$\frac{C V^2}{2d}$

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(C) The force of attraction $F$ between the plates of a parallel plate capacitor is given by the formula:$F = \frac{Q^2}{2 \varepsilon_0 A}$where $Q$ is the charge on the capacitor,$\varepsilon_0$ is the permittivity of free space,and $A$ is the area of each plate.We know that the charge $Q$ is related to capacitance $C$ and potential difference $V$ by:$Q = CV$Also,the capacitance of a parallel plate capacitor is given by:$C = \frac{\varepsilon_0 A}{d} \implies \varepsilon_0 A = Cd$Substituting these expressions into the force formula:$F = \frac{(CV)^2}{2(Cd)}$$F = \frac{C^2 V^2}{2Cd}$$F = \frac{CV^2}{2d}$

$A$ parallel plate air capacitor has capacity $C$,distance of separation between plates is $d$,and potential difference $V$ is applied between the plates. The force of attraction between the plates of the parallel plate air capacitor is

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