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(B) Let the capacitance of the capacitor be $C$ and the electromotive force of the battery be $V$. When the capacitor is connected to the battery,the

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Half of the energy supplied is stored in the capacitor.

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(B) Let the capacitance of the capacitor be $C$ and the electromotive force of the battery be $V$. When the capacitor is connected to the battery,the total work done by the battery is $W = QV = (CV)V = CV^2$. The energy stored in the capacitor is $U = \frac{1}{2} CV^2$. Comparing the two,we see that the energy stored in the capacitor is exactly half of the total energy supplied by the battery $(U = \frac{1}{2} W)$. The remaining half of the energy is dissipated as heat in the connecting wires or during the charging process.

When an uncharged capacitor is connected to a battery to charge it fully,

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