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(C) The energy stored in a capacitor is given by the formula $U = \frac{1}{2} C_{eq} V^2$.Since the voltage $V$ is constant for all combinations,the e

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Three in parallel

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(C) The energy stored in a capacitor is given by the formula $U = \frac{1}{2} C_{eq} V^2$.Since the voltage $V$ is constant for all combinations,the energy $U$ is directly proportional to the equivalent capacitance $C_{eq}$.To maximize the energy $U$,we must maximize the equivalent capacitance $C_{eq}$.For $n$ identical capacitors of capacitance $C$:$1$. In series: $C_{eq} = \frac{C}{n} = \frac{C}{3}$.$2$. In parallel: $C_{eq} = nC = 3C$.$3$. Two in parallel and one in series: $C_{eq} = \frac{(2C) \cdot C}{2C + C} = \frac{2}{3}C$.$4$. Two in series and one in parallel: $C_{eq} = \frac{C}{2} + C = 1.5C$.Comparing these values,the parallel combination $(3C)$ provides the maximum equivalent capacitance. Therefore,the combination with three capacitors in parallel stores the greatest energy.

Three identical capacitors are combined in different ways. For the same voltage applied to each combination,the one that stores the greatest energy is:

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