(D) When a copper sheet of thickness $l$ is inserted between the plates of a parallel plate capacitor (separation $d$),the electric field inside the c

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(D) When a copper sheet of thickness $l$ is inserted between the plates of a parallel plate capacitor (separation $d$),the electric field inside the copper is zero.This effectively reduces the separation between the plates to $(d-l)$.The original capacitance is $C = \frac{\epsilon_0 A}{d}$.The new capacitance is $C_{eq} = \frac{\epsilon_0 A}{d-l}$.Since $(d-l) C$.Furthermore,the capacitance $C_{eq}$ depends only on the thickness $l$ and not on the position of the sheet between the plates.Therefore,the capacitance is greater than the initial value and remains invariant for all positions of the sheet between the plates.

Class 12 Physics Electric Potential and Capacitance Effect of Dielectric Inside Capacitor

$A$ parallel plate capacitor has a parallel sheet of copper inserted between and parallel to the two plates,without touching the plates. The capacity of the capacitor after the introduction of the copper sheet is:

A
minimum when the copper sheet touches one of the plates.
B
greater than that before introducing the sheet.
C
invariant for all positions of the sheet between the plates.
D
$B$ and $C$ both

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Electric Potential and Capacitance

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Effect of Dielectric Inside Capacitor

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$A$ parallel plate capacitor has a parallel sheet of copper inserted between and parallel to the two plates,without touching the plates. The capacity of the capacitor after the introduction of the copper sheet is:

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In a parallel plate capacitor, the radius of each circular plate is $12\,cm$ and the distance between the plates is $5\,mm$. A glass slab of $3\,mm$ thickness and radius $12\,cm$ with a dielectric constant of $6$ is placed between the plates. The capacitance of the capacitor will be:

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