A parallel plate capacitor is charged by conn | vedclass

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(A) According to the modified Ampere's circuital law,the total current is the sum of conduction current $(I_C)$ and displacement current $(I_D)$: $\oi

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Displacement current of magnitude equal to $I$ flows in the same direction as $I$.

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(A) According to the modified Ampere's circuital law,the total current is the sum of conduction current $(I_C)$ and displacement current $(I_D)$: $\oint B \cdot dl = \mu_0(I_C + I_D)$.In the wire,there is only conduction current $I_C = I$,and the displacement current $I_D = 0$.In the gap between the plates,there is no conduction current $(I_C = 0)$,but the changing electric field produces a displacement current $I_D$.By the principle of continuity of current,the displacement current in the gap must be equal to the conduction current in the wire,i.e.,$I_D = I_C = I$.This displacement current flows in the same direction as the conduction current to maintain the continuity of the total current in the circuit.

$A$ parallel plate capacitor is charged by connecting it to a battery through a resistor. If $I$ is the current in the circuit,then in the gap between the plates:

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