$A$ particle $A$ has charge $+q$ and particle $B$ has charge $+4q$,with each of them having the same mass $m$. When allowed to fall from rest through the same electric potential difference $V$,the ratio of their speeds $\frac{v_A}{v_B}$ will be:

  • A
    $1: 2$
  • B
    $2: 1$
  • C
    $1: 4$
  • D
    $4: 1$

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