$A$ particle in $SHM$ is described by the displacement equation $x(t) = A\cos(\omega t + \theta)$. If the initial $(t = 0)$ position of the particle is $1 \, cm$ and its initial velocity is $\pi \, cm/s$,what is its amplitude? The angular frequency of the particle is $\pi \, s^{-1}$.
- A$1 \, cm$
- B$\sqrt{2} \, cm$
- C$2 \, cm$
- D$2.5 \, cm$
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DifficultAP EAMCET 2012
View SolutionThe displacement of a body executing $SHM$ is given by $x = A \sin (2\pi t + \pi /3).$ The first time from $t = 0$ when the velocity is maximum is .... $\sec$
Medium
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