A particle initially at rest is subjected to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the constant force be $F$ and the retarding force be $-kv$,where $k$ is a positive constant and $v$ is the velocity.The net force on the parti

Vedclass · Accepted Answer

Both $(B)$ and $(C)$

Vedclass · Answer

(D) Let the constant force be $F$ and the retarding force be $-kv$,where $k$ is a positive constant and $v$ is the velocity.The net force on the particle is $F_{net} = F - kv$.According to Newton's second law,$ma = F - kv$,where $a = dv/dt$.Initially,at $t = 0$,$v = 0$,so the initial acceleration is $a_0 = F/m$.As the particle moves,$v$ increases,which causes the retarding force $kv$ to increase.Consequently,the net force $F - kv$ decreases,meaning the acceleration $a = (F - kv)/m$ decreases from its initial value $F/m$ towards zero.As $t 	o \infty$,the acceleration approaches zero,and the velocity approaches a constant terminal value $v_t = F/k$ where the net force becomes zero.Thus,both statements $(B)$ and $(C)$ are correct.

$A$ particle initially at rest is subjected to two forces. One is constant,the other is a retarding force proportional to the particle velocity. In the subsequent motion of the particle,

Similar Questions

Three forces of magnitude $F_1, F_2$ and $F_3$ act on a body located at the origin as shown in the figure. The condition that gives zero net force is

Explain why
$(a)$ a horse cannot pull a cart and run in empty space,
$(b)$ passengers are thrown forward from their seats when a speeding bus stops suddenly,
$(c)$ it is easier to pull a lawn mower than to push it,
$(d)$ a cricketer moves his hands backwards while holding a catch.

$A$ particle of mass $m$ is acted upon by a force $F$ given by the empirical law $F = \frac{R}{t^2} v(t)$. If this law is to be tested experimentally by observing the motion starting from rest,the best way is to plot:

$A$ car of mass $500\, kg$ is driven with acceleration $1\, m/s^2$ along a straight level road against a constant external resistance of $1000\, N$. When the velocity is $5\, m/s$,the rate at which the engine is working is .............. $kW$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module