$A$ particle is moving in a circle of radius $R$ with constant speed $v$. If the radius is doubled while keeping the speed the same,what happens to the centripetal force?

$A$ cyclist is riding with a speed of $36 \,km/h$. As he approaches a circular turn on the road of radius $50 \,m$, he applies brakes and reduces his speed at the constant rate of $0.5 \,m/s^2$. The magnitude and direction of the net acceleration of the cyclist on the circular turn are respectively:

$A$ particle is in uniform circular motion. The equation of its trajectory is given by $(x-2)^2+y^2=25$,where $x$ and $y$ are in meters. The speed of the particle is $2 \text{ m/s}$. When the particle attains the lowest $y$ coordinate,the acceleration of the particle is (in $\text{m/s}^2$):

In circular motion,the centripetal acceleration is given by

$A$ car moves with a speed of $30 \, m/s$ on a circular path of radius $500 \, m$. If its tangential acceleration is $2 \, m/s^2$,what is the magnitude of the total acceleration of the car in $m/s^2$?

$A$ particle moves on a circular path with decreasing speed. Identify the correct statement.