A particle of mass m and charge q moves with | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When a charged particle enters a perpendicular magnetic field,it follows a circular path of radius $r$ given by the balance between the magnetic f

Vedclass · Accepted Answer

$q(b - a)B/m$

Vedclass · Answer

(B) When a charged particle enters a perpendicular magnetic field,it follows a circular path of radius $r$ given by the balance between the magnetic force and the centripetal force:$qvB = \frac{mv^2}{r}$Rearranging for velocity,we get:$v = \frac{qBr}{m}$For the particle to just enter the region $x > b$,the radius of its circular path must be at least equal to the width of the magnetic field region,which is $(b - a)$.Thus,the minimum radius required is $r_{\min} = b - a$.Substituting this into the velocity equation:$v_{\min} = \frac{qB(b - a)}{m}$Therefore,the correct option is $B$.

Similar Questions

Which one of the following does not readily give oxygen upon heating?

The phenomenon of 'industrial melanism' demonstrates:

$A$ plane $\pi$ makes intercepts $3$ and $4$ respectively on $Z$-axis and $X$-axis. If $\pi$ is parallel to $Y$-axis,then its equation is:

$A$ body of mass $m$ and radius of gyration $K$ has an angular momentum $L$. Then its angular velocity is

Vedclass Test Series

Exam Paper Generator

Online Exam Module