A particle of mass m strikes the ground inela | vedclass

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Question

(B) Let the velocity of the particle before impact be $u$ and after impact be $v$.The component of velocity parallel to the ground remains unchanged b

Vedclass · Accepted Answer

$\frac{	an 	heta}{	an \alpha} = e$

Vedclass · Answer

(B) Let the velocity of the particle before impact be $u$ and after impact be $v$.The component of velocity parallel to the ground remains unchanged because there is no impulsive force acting parallel to the surface:$v \sin \alpha = u \sin 	heta$  --- $(1)$The component of velocity perpendicular to the ground changes according to the coefficient of restitution $e$:$v \cos \alpha = e u \cos 	heta$  --- $(2)$Dividing equation $(1)$ by equation $(2)$:$\frac{v \sin \alpha}{v \cos \alpha} = \frac{u \sin 	heta}{e u \cos 	heta}$$	an \alpha = \frac{	an 	heta}{e}$Rearranging the terms,we get:$\frac{	an 	heta}{	an \alpha} = e$

$A$ particle of mass $m$ strikes the ground inelastically with a coefficient of restitution $e$. Find the relation between the angles $\theta$ and $\alpha$ as shown in the figure.

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