$A$ particle of mass $10 \text{ g}$ is executing simple harmonic motion with an amplitude of $0.5 \text{ m}$ and a periodic time of $(\pi / 5) \text{ s}$. The maximum value of the force acting on the particle is ... $N$.

$A$ point mass oscillates along the $x$-axis according to the law $x = x_0 \cos(\omega t + \pi/4)$. If the acceleration of the particle is written as $a = A \cos(\omega t + \delta)$,then:

$A$ body of mass $0.4 \text{ kg}$ performs simple harmonic motion. It experiences a restoring force of $0.4 \text{ N}$ when its displacement from the mean position is $4 \text{ cm}$. The force constant and magnitude of acceleration respectively are

The amplitude of a particle executing $S.H.M.$ with a frequency of $60 \, Hz$ is $0.01 \, m$. The maximum value of the acceleration of the particle is

$A$ particle of mass $10 \, g$ performs simple harmonic motion with an amplitude of $0.5 \, m$ and an angular frequency of $10 \, rad/s$. What is the maximum force acting on it in $N$?

For a particle performing $S.H.M.$, the displacement-time graph is shown. For that particle, the force-time graph is correctly represented by which of the following?