A particle of mass 0.6, g and having a charge | vedclass

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(C) For the particle to move with a uniform velocity,the net force acting on it must be zero. This means the magnetic force must balance the gravitati

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$20\, T$

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(C) For the particle to move with a uniform velocity,the net force acting on it must be zero. This means the magnetic force must balance the gravitational force acting on the particle.$|F_m| = mg$Since the magnetic force is given by $F_m = qvB$ (assuming the magnetic field is perpendicular to the velocity),we have:$qvB = mg$$B = \frac{mg}{qv}$Given:$m = 0.6\, g = 0.6 	imes 10^{-3}\, kg$$q = 25\, nC = 25 	imes 10^{-9}\, C$$v = 1.2 	imes 10^4\, m/s$$g = 10\, m/s^2$Substituting the values:$B = \frac{0.6 	imes 10^{-3} 	imes 10}{25 	imes 10^{-9} 	imes 1.2 	imes 10^4}$$B = \frac{6 	imes 10^{-3}}{30 	imes 10^{-5}}$$B = \frac{6 	imes 10^{-3}}{0.3 	imes 10^{-3}} = \frac{6}{0.3} = 20\, T$Thus,the magnetic induction is $20\, T$.

$A$ particle of mass $0.6\, g$ and having a charge of $25\, nC$ is moving horizontally with a uniform velocity $1.2 \times 10^4\, m/s$ in a uniform magnetic field. If the particle continues to move with uniform velocity,the value of the magnetic induction is $(g = 10\, m/s^2)$.

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