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(D) The angular displacement is given by $	heta = 0.025t^2 - 0.1t$.The angular velocity $\omega$ is the first derivative of angular displacement with

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Constant $0.05 \, rad/s^2$

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(D) The angular displacement is given by $	heta = 0.025t^2 - 0.1t$.The angular velocity $\omega$ is the first derivative of angular displacement with respect to time:$\omega = \frac{d	heta}{dt} = \frac{d}{dt}(0.025t^2 - 0.1t) = 0.05t - 0.1 \, rad/s$.The angular acceleration $\alpha$ is the derivative of angular velocity with respect to time:$\alpha = \frac{d\omega}{dt} = \frac{d}{dt}(0.05t - 0.1) = 0.05 \, rad/s^2$.Since the result is independent of time $t$,the angular acceleration is constant at $0.05 \, rad/s^2$.

$A$ particle starts rotating from rest. Its angular displacement is expressed by the following equation $\theta = 0.025t^2 - 0.1t$,where $\theta$ is in radians and $t$ is in seconds. The angular acceleration of the particle is:

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