A pendulum clock is placed inside an elevator | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The time period of a simple pendulum is given by $T = 2\pi \sqrt{\frac{L}{g_{eff}}}$,where $g_{eff}$ is the effective acceleration due to gravity.

Vedclass · Accepted Answer

Shows correct time when descending with constant speed.

Vedclass · Answer

(C) The time period of a simple pendulum is given by $T = 2\pi \sqrt{\frac{L}{g_{eff}}}$,where $g_{eff}$ is the effective acceleration due to gravity.When an elevator moves with constant velocity (constant speed in a straight line),its acceleration is zero.In this case,the effective acceleration $g_{eff} = g$,which is the same as when the elevator is at rest.Therefore,the time period $T$ remains unchanged,and the clock shows the correct time.If the elevator accelerates,$g_{eff}$ changes $(g_{eff} = g \pm a)$,causing the clock to gain or lose time.

$A$ pendulum clock is placed inside an elevator. Under what condition does it show the correct time?

Similar Questions

$A$ simple pendulum of length $1 \,m$ is freely suspended from the ceiling of an elevator. The time period of small oscillations as the elevator moves up with an acceleration of $2 \,m/s^2$ is (use $g=10 \,m/s^2$).

The time period of a simple pendulum is $T$. The time taken to complete $5/8$ oscillations starting from the mean position is $\frac{\alpha}{\beta} T$. The value of $\alpha$ is ..... .

$A$ pendulum clock is running fast. To correct its time,we should

The time period of a simple pendulum in a lift descending with constant acceleration $g$ is

The motion of a simple pendulum executing $S.H.M.$ is represented by the following equation:
$Y = A \sin (\pi t + \phi)$,where time is measured in $seconds$.
The length of the pendulum is .............$cm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module