A person can throw a ball up to a maximum ran | vedclass

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(B) The maximum horizontal range $R_{\max}$ of a projectile is given by the formula $R_{\max} = \frac{u^2}{g}$,where $u$ is the initial velocity and $

Vedclass · Accepted Answer

$50$

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(B) The maximum horizontal range $R_{\max}$ of a projectile is given by the formula $R_{\max} = \frac{u^2}{g}$,where $u$ is the initial velocity and $g$ is the acceleration due to gravity.Given $R_{\max} = 100 \, m$,we have $\frac{u^2}{g} = 100 \, m$.The maximum height $H_{\max}$ reached by a projectile when thrown vertically upwards is given by $H_{\max} = \frac{u^2}{2g}$.Substituting the value of $\frac{u^2}{g}$ into the height formula:$H_{\max} = \frac{1}{2} 	imes \left(\frac{u^2}{g}ight) = \frac{1}{2} 	imes 100 \, m = 50 \, m$.Therefore,the person can throw the ball to a maximum height of $50 \, m$.

$A$ person can throw a ball up to a maximum range of $100 \, m$. How high above the ground can he throw the same ball (in $, m$)?

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