A plane wavefront (lambda = 6 times 10^{-7} , | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For secondary maxima in single slit diffraction,the condition is given by $d \sin 	heta = (n + \frac{1}{2}) \lambda$,where $n$ is the order of th

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(A) For secondary maxima in single slit diffraction,the condition is given by $d \sin 	heta = (n + \frac{1}{2}) \lambda$,where $n$ is the order of the maximum.For the second maximum,$n = 2$,so $d \sin 	heta = \frac{5\lambda}{2}$.Since $	heta$ is very small,$\sin 	heta \approx 	heta = \frac{x}{f}$,where $x$ is the distance from the central axis and $f$ is the focal length.Thus,$d \cdot \frac{x}{f} = \frac{5\lambda}{2} \implies x = \frac{5\lambda f}{2d}$.The linear diameter of the second maximum is the distance between the second maxima on either side of the central axis,which is $2x$.$2x = \frac{5\lambda f}{d} = \frac{5 	imes (6 	imes 10^{-7} \, m) 	imes 0.8 \, m}{0.4 	imes 10^{-3} \, m}$.$2x = \frac{24 	imes 10^{-7}}{0.4 	imes 10^{-3}} = 60 	imes 10^{-4} \, m = 6 	imes 10^{-3} \, m = 6 \, mm$.

$A$ plane wavefront $(\lambda = 6 \times 10^{-7} \, m)$ falls on a slit $0.4 \, mm$ wide. $A$ convex lens of focal length $0.8 \, m$ placed behind the slit focuses the light on a screen. What is the linear diameter of the second maximum in $mm$?

Similar Questions

Consider sunlight incident on a slit of width $10^4 \ \mathring{A}$. The image seen through the slit shall

In the diffraction due to a single slit,the central fringe ...

Light appears to travel in straight lines since

Diffraction effects are easier to notice in the case of sound waves than in the case of light waves because

Assertion: The clouds in the sky generally appear to be whitish.
Reason: Diffraction due to clouds is efficient in equal measure at all wavelengths.

Vedclass Test Series

Exam Paper Generator

Online Exam Module