A point object in air is in front of the curv | vedclass

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(C) The Lens-Maker's formula is given by $\frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$.For a plano-convex lens,the radius of

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$60$

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(C) The Lens-Maker's formula is given by $\frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$.For a plano-convex lens,the radius of curvature of the curved surface is $R_1 = 30 \; cm$ and the flat surface has an infinite radius of curvature,so $R_2 = \infty$.The refractive index of the lens material is $\mu = 1.5$.Substituting these values into the formula:$\frac{1}{f} = (1.5 - 1) \left( \frac{1}{30} - \frac{1}{\infty} \right)$$\frac{1}{f} = (0.5) \left( \frac{1}{30} - 0 \right)$$\frac{1}{f} = \frac{0.5}{30} = \frac{1}{60}$Therefore,the focal length $f = 60 \; cm$.

$A$ point object in air is in front of the curved surface of a plano-convex lens. The radius of curvature of the curved surface is $30 \; cm$ and the refractive index of the lens material is $1.5$. Then the focal length of the lens (in $cm$) is:

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