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(B) Let the two mirrors be $M$ and $M'$. The object $O$ is placed at a distance $a/2$ from both mirrors.For mirror $M$,the $1^{st}$ image $I_1$ is at

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$2na$

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(B) Let the two mirrors be $M$ and $M'$. The object $O$ is placed at a distance $a/2$ from both mirrors.For mirror $M$,the $1^{st}$ image $I_1$ is at distance $a/2$ behind $M$. The $2^{nd}$ image $I_2$ is formed by reflection of $I_1'$ in $M$,at distance $a/2 + a + a = 5a/2$ from $M$.In general,the distance of the $n^{th}$ order image from the mirror is given by $d_n = (n - 1/2)a$ or similar patterns depending on the sequence.Looking at the provided figure,the $n^{th}$ order images $I_n$ and $I_n'$ are located at a distance of $(n - 1/2)a + a/2 = na$ from the respective mirrors.The total distance between the $n^{th}$ order image formed in mirror $M$ and the $n^{th}$ order image formed in mirror $M'$ is the sum of their distances from the mirrors plus the distance between the mirrors.Specifically,the distance between the $n^{th}$ order image $I_n$ and $I_n'$ is $2na$.

$A$ point object is placed mid-way between two plane mirrors at a distance $a$ apart. The plane mirrors form an infinite number of images due to multiple reflections. The distance between the $n^{th}$ order images formed in the two mirrors is

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