A polarized light of intensity I_0 is passed | vedclass

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(C) According to Malus's law,the intensity of polarized light transmitted through a polarizer is given by the formula:$I = I_0 \cos^2 	heta$where $I_

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$I = \frac{I_0}{4}$

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(C) According to Malus's law,the intensity of polarized light transmitted through a polarizer is given by the formula:$I = I_0 \cos^2 	heta$where $I_0$ is the intensity of the incident polarized light,$	heta$ is the angle between the pass axis of the polarizer and the plane of polarization of the incident light.Given:$I_0 = I_0$$	heta = 60^o$Substituting the values into the formula:$I = I_0 \cos^2(60^o)$Since $\cos(60^o) = \frac{1}{2}$,we have:$I = I_0 \left(\frac{1}{2}ight)^2$$I = I_0 \left(\frac{1}{4}ight)$$I = \frac{I_0}{4}$Therefore,the intensity of the emergent polarized light is $\frac{I_0}{4}$.

$A$ polarized light of intensity $I_0$ is passed through another polarizer whose pass axis makes an angle of $60^o$ with the pass axis of the former. What is the intensity of emergent polarized light from the second polarizer?

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