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(C) The potential gradient $(x)$ is defined as the potential drop per unit length of the wire, given by $x = \frac{V}{L}$.Since $V = IR$ and $R = \fra

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$10^{-2} \, V/m$

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(C) The potential gradient $(x)$ is defined as the potential drop per unit length of the wire, given by $x = \frac{V}{L}$.Since $V = IR$ and $R = \frac{ho L}{A}$, we can substitute these into the expression for the potential gradient:$x = \frac{I \cdot (ho L / A)}{L} = \frac{I ho}{A}$.Given values are:Current $(I) = 0.1 \, A$,Resistivity $(ho) = 10^{-7} \, \Omega \cdot m$,Area $(A) = 10^{-6} \, m^2$.Substituting these values into the formula:$x = \frac{0.1 	imes 10^{-7}}{10^{-6}} = \frac{10^{-1} 	imes 10^{-7}}{10^{-6}} = \frac{10^{-8}}{10^{-6}} = 10^{-2} \, V/m$.

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