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(B) The efficiency $\eta$ of a transformer is defined as the ratio of output power $P_s$ to input power $P_p$,i.e.,$\eta = \frac{P_s}{P_p}$.Given: Inp

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$45$

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(B) The efficiency $\eta$ of a transformer is defined as the ratio of output power $P_s$ to input power $P_p$,i.e.,$\eta = \frac{P_s}{P_p}$.Given: Input voltage $V_p = 2300 \, V$,Input current $I_p = 5 \, A$,Output voltage $V_s = 230 \, V$,and Efficiency $\eta = 90 \% = 0.9$.Input power $P_p = V_p 	imes I_p = 2300 \, V 	imes 5 \, A = 11500 \, W$.Output power $P_s = \eta 	imes P_p = 0.9 	imes 11500 \, W = 10350 \, W$.Since $P_s = V_s 	imes I_s$,the output current $I_s = \frac{P_s}{V_s} = \frac{10350 \, W}{230 \, V} = 45 \, A$.

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