A projectile is thrown upward with a velocity | vedclass

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(B) The initial velocity vector is $\vec{u} = v_0 \cos \alpha \hat{i} + v_0 \sin \alpha \hat{j}$.At the same horizontal plane,the final velocity vecto

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$2 v_0 \sin \alpha$ vertically downwards

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(B) The initial velocity vector is $\vec{u} = v_0 \cos \alpha \hat{i} + v_0 \sin \alpha \hat{j}$.At the same horizontal plane,the final velocity vector is $\vec{v} = v_0 \cos \alpha \hat{i} - v_0 \sin \alpha \hat{j}$.The change in velocity is $\Delta \vec{v} = \vec{v} - \vec{u}$.$\Delta \vec{v} = (v_0 \cos \alpha \hat{i} - v_0 \sin \alpha \hat{j}) - (v_0 \cos \alpha \hat{i} + v_0 \sin \alpha \hat{j})$.$\Delta \vec{v} = -2 v_0 \sin \alpha \hat{j}$.The magnitude of the change in velocity is $2 v_0 \sin \alpha$,and the negative sign indicates it is directed vertically downwards.

$A$ projectile is thrown upward with a velocity $v_0$ at an angle $\alpha$ to the horizontal. The change in velocity of the projectile when it strikes the same horizontal plane is

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