A racing car has an acceleration of 4, m s^{- | vedclass

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(B) Given: Initial velocity $u = 0\, m s^{-1}$,acceleration $a = 4\, m s^{-2}$,and time $t = 20\, s$.To find the distance $S$ covered,we use the secon

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$800$

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(B) Given: Initial velocity $u = 0\, m s^{-1}$,acceleration $a = 4\, m s^{-2}$,and time $t = 20\, s$.To find the distance $S$ covered,we use the second equation of motion:$S = ut + \frac{1}{2}at^2$Substituting the given values:$S = (0 	imes 20) + \frac{1}{2} 	imes 4 	imes (20)^2$$S = 0 + 2 	imes 400$$S = 800\, m$Therefore,the car will cover a distance of $800\, m$ in $20\, s$.

$A$ racing car has an acceleration of $4\, m s^{-2}$. What distance will it cover in $20\, s$ after the start (in $, m$)?

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