A radio isotope has a half-life of 75, text{y | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The number of half-lives $n$ in a time $t$ is given by $n = \frac{t}{T_{1/2}}$.Given $t = 150\, 	ext{years}$ and $T_{1/2} = 75\, 	ext{years}$, w

Vedclass · Accepted Answer

$75$

Vedclass · Answer

(D) The number of half-lives $n$ in a time $t$ is given by $n = \frac{t}{T_{1/2}}$.Given $t = 150\, 	ext{years}$ and $T_{1/2} = 75\, 	ext{years}$, we have $n = \frac{150}{75} = 2$.The fraction of atoms remaining after $n$ half-lives is given by $N/N_0 = (1/2)^n$.Substituting $n = 2$, we get $N/N_0 = (1/2)^2 = 1/4 = 0.25$.The fraction of atoms that have decayed is $1 - N/N_0 = 1 - 0.25 = 0.75$.To express this as a percentage, we multiply by $100$, which gives $0.75 	imes 100 = 75\%$.

$A$ radio isotope has a half-life of $75\, \text{years}$. The fraction of the atoms of this material that would decay in $150\, \text{years}$ will be...........$\%$

Similar Questions

The half-life of $Bi^{210}$ is $5$ days. If we start with $50,000$ atoms of this isotope,the number of atoms left over after $10$ days is:

The half-life of a radioactive substance is $30 \text{ minutes}$. The time taken between $40 \%$ decay and $85 \%$ decay of the same radioactive substance is

If the decay or disintegration constant of a radioactive substance is $\lambda$,then its half-life and mean life are respectively:

The decay constant of radium is $4.28 \times 10^{-4}$ per year. Its half-life will be .......... $years$.

Give the different units of radioactivity and define them.

Vedclass Test Series

Exam Paper Generator

Online Exam Module