(C) The formula for radioactive decay is $N_t = N_o (1/2)^n$,where $n$ is the number of half-lives.First,calculate the number of half-lives $(n)$: $n

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(C) The formula for radioactive decay is $N_t = N_o (1/2)^n$,where $n$ is the number of half-lives.First,calculate the number of half-lives $(n)$: $n = \frac{26 \ hr}{6.5 \ hr} = 4$.Now,substitute the values into the formula: $N_t = 48 \times 10^{19} \times (1/2)^4$.$N_t = 48 \times 10^{19} \times \frac{1}{16}$.$N_t = 3 \times 10^{19}$ atoms.

Class 12 Chemistry Nuclear Chemistry Rate of decay and Half-life

Medium

$A$ radioactive element with half-life $6.5 \ hr$ has $48 \times 10^{19}$ atoms. Number of atoms left after $26 \ hr$ is:

A
$24 \times 10^{19}$
B
$12 \times 10^{19}$
C
$3 \times 10^{19}$
D
$6 \times 10^{19}$

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$A$ radioactive element with half-life $6.5 \ hr$ has $48 \times 10^{19}$ atoms. Number of atoms left after $26 \ hr$ is:

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