A rational number between sqrt{2} and sqrt{3} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) We know that $\sqrt{2} \approx 1.414$ and $\sqrt{3} \approx 1.732$.$A$ rational number is a number that can be expressed in the form $\frac{p}{q}$

Vedclass · Accepted Answer

$1.5$

Vedclass · Answer

(A) We know that $\sqrt{2} \approx 1.414$ and $\sqrt{3} \approx 1.732$.$A$ rational number is a number that can be expressed in the form $\frac{p}{q}$,where $p$ and $q$ are integers and $q 
eq 0$.Comparing the given options:$1.5 = \frac{15}{10} = \frac{3}{2}$,which is a rational number.Since $1.414 Option $B$ and $C$ involve irrational numbers,so they are not rational numbers.Option $D$ $(1.8)$ is greater than $\sqrt{3} \approx 1.732$,so it does not lie between them.Therefore,$1.5$ is the correct rational number.

$A$ rational number between $\sqrt{2}$ and $\sqrt{3}$ is

Similar Questions

Fill in the blanks to make the following statement true: $\sqrt{2} \cdot \sqrt{3} \cdot \sqrt{6} = \dots$

If $(\frac{2}{5})^{5} \times (\frac{25}{4})^{3} = (\frac{5}{2})^{3x-2}$,then find $x$.

Prove that $(1^{3}+2^{3}+3^{3}+4^{3}+5^{3})^{\frac{1}{2}} = (1^{3}+2^{3}+3^{3}+4^{3})^{\frac{1}{2}} + (5^{3})^{\frac{1}{3}}$.

Insert a rational number and an irrational number between the following:
$\frac{-2}{5}$ and $\frac{1}{2}$

Express the following in the form $\frac{p}{q},$ where $p$ and $q$ are integers and $q \neq 0.$
$0.\overline{125}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module