A ray of light is incident at an angle of 60^ | vedclass

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(A) The deviation produced by a prism is given by the formula $\delta = i + e - A$,where $i$ is the angle of incidence,$e$ is the angle of emergence,a

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Normal to the face through which it emerges

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(A) The deviation produced by a prism is given by the formula $\delta = i + e - A$,where $i$ is the angle of incidence,$e$ is the angle of emergence,and $A$ is the prism angle.Given: $i = 60^o$,$A = 30^o$,and $\delta = 30^o$.Substituting these values into the formula: $30^o = 60^o + e - 30^o$.Solving for $e$: $e = 30^o + 30^o - 60^o = 0^o$.Since the angle of emergence $e$ is $0^o$,the emergent ray is normal (perpendicular) to the surface of the prism.Therefore,the emergent ray makes an angle of $90^o$ with the face through which it emerges.

$A$ ray of light is incident at an angle of $60^o$ on one face of a prism of angle $30^o$. The ray emerging out of the prism makes an angle of $30^o$ with the incident ray. The emergent ray is

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