A rectangular loop is being pulled at a const | vedclass

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(B) As the loop enters the magnetic field,the magnetic flux $\phi$ through the loop increases. According to Faraday's law,the induced emf is $E = -\fr

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(B) As the loop enters the magnetic field,the magnetic flux $\phi$ through the loop increases. According to Faraday's law,the induced emf is $E = -\frac{d\phi}{dt}$. Since the flux is increasing,the induced emf is negative and constant while the loop is entering. When the loop is completely inside the magnetic field,the magnetic flux through it remains constant,so $\frac{d\phi}{dt} = 0$,which means the induced emf $E = 0$. As the loop exits the magnetic field,the magnetic flux through the loop decreases. According to Lenz's law,the induced emf will be positive and constant while the loop is exiting. Therefore,the graph of $E$ versus $x$ shows a negative constant value during entry,zero value when fully inside,and a positive constant value during exit. This corresponds to the graph shown in option $B$.

$A$ rectangular loop is being pulled at a constant speed $v$,through a region of certain thickness $d$,in which a uniform magnetic field $B$ is set up. The graph between position $x$ of the right-hand edge of the loop and the induced emf $E$ will be

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