The bob of a simple pendulum is replaced by a magnet. The oscillations are set along the length of the magnet. $A$ copper coil is added so that one pole of the magnet passes in and out of the coil. The coil is short-circuited. Then which one of the following happens?

The physical quantity which is measured in the unit of $\text{wb A}^{-1}$ is

$A$ flat coil of $500$ turns,each of area $50 \,cm^2$,rotates in a uniform magnetic field of $0.14 \,Wb/m^2$ about an axis normal to the field at an angular speed of $150 \,rad/s$. The coil has a resistance of $5 \,\Omega$. The induced $e.m.f.$ is applied to an external resistance of $10 \,\Omega$. The peak current through the resistance is .......... $A$. (in $.5$)

In the $LR$ circuit shown,what is the variation of the current $I$ as a function of time? The switch is closed at time $t = 0 \, s.$

$A$ rectangular loop is being pulled at a constant speed $v$,through a region of certain thickness $d$,in which a uniform magnetic field $B$ is set up. The graph between position $x$ of the right-hand edge of the loop and the induced emf $E$ will be

The switch $S$ of the circuit shown in the figure is closed at $t = 0$. If $e$ denotes the induced emf in the inductor $L$ and $i$ denotes the current flowing through the circuit at time $t$,which of the following graphs correctly represents the variation of $e$ with time $t$?