A room without a ceiling is 12 , m long,4 , m | vedclass

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(C) For a given room,the dimensions are: length $(l) = 12 \, m$,width $(b) = 4 \, m$,and height $(h) = 3 \, m$.The longest rod that can be placed in a

Vedclass · Accepted Answer

$13$

Vedclass · Answer

(C) For a given room,the dimensions are: length $(l) = 12 \, m$,width $(b) = 4 \, m$,and height $(h) = 3 \, m$.The longest rod that can be placed in a rectangular room corresponds to the space diagonal of the cuboid.The formula for the length of the diagonal is $d = \sqrt{l^2 + b^2 + h^2}$.Substituting the given values:$d = \sqrt{12^2 + 4^2 + 3^2} \, m$$d = \sqrt{144 + 16 + 9} \, m$$d = \sqrt{169} \, m$$d = 13 \, m$.Thus,the length of the longest rod is $13 \, m$.

$A$ room without a ceiling is $12 \, m$ long,$4 \, m$ wide,and $3 \, m$ high. Find the length of the longest rod that can be placed in that room. (in $m$)

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